Evaluate the following integral ∫_0^1x e^(x^2 ) dx
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total answers (1)
total answers (1)
Mathematics
∫_0^1x e^(x^2 ) dx
need an explanation for this answer? contact us directly to get an explanation for this answer=1/2 ∫_0^1〖e^(x^2 ) (2x)〗 dx=1/2 [e^(x^2 ) ]_0^1=1/2(e-1)