Evaluate the following integral ∫_1^2x/(x^2+1) dx
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total answers (1)
total answers (1)
Mathematics
I=1/2 ∫_1^22x/(x^2+1) dx=1/2 〖ln(x^2+1)〗_1^2=1/2 [ln5-ln2 ]=1/2 ln(5/2)
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