Evaluate the following integral ∫_0^(π⁄2)〖〖cos〗^2 x〗 dx

∫_0^(π⁄2)〖〖cos〗^2 x〗 dx=1/2 ∫_0^(π⁄2)(1+cos2x ) dx=1/2 [x+1/2 sin2x ]_0^(π⁄2)=π/4

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∫_0^(π⁄2)〖〖cos〗^2 x〗 dx=1/2 ∫_0^(π⁄2)(1+cos2x ) dx=1/2 [x+1/2 sin2x ]_0^(π⁄2)=π/4

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