Evaluate the following integral ∫e^x/(e^x+1) dx
Put z =e^x then dz=e^x dx1=∫dz/(z+1)=ln|z+1|+c=ln|x^x+1|+c
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Put z =e^x then dz=e^x dx
need an explanation for this answer? contact us directly to get an explanation for this answer1=∫dz/(z+1)=ln|z+1|+c=ln|x^x+1|+c