Q:

Calculate the area between y=x^2 and y=-2x+3.

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Calculate the area between y=x^2 and y=-2x+3.

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Solving the two equations to get:
x^2+2x-3=0
∴(x+3)(x-1)=0
∴x=1  or  x=-3
And the required area is:
A=∫_a^b|f(x)-g(x)|  dx=∫_(-3)^1(-2x+3-x^2 )  dx
=[-x^2+3x-1/3 x^3 ]_(-3)^1=[-1+3-1/3]-[-9-9+9]=32/3  square units

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