Q:

Calculate the area between y=(e^x+1)/e^x and y=1 and to the right of x=0.

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Calculate the area between    y=(e^x+1)/e^x    and  y=1  and to the right of x=0.

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It is clear that:
lim(x→∞)⁡(f(x)-g(x))=lim⁡((e^x+1)/e^x -1)=lim(x→∞)⁡〖1/e^x 〗=0
Therefore:
A=∫_0^∞((e^x+1)/e^x -1)  dx=lim(t→∞)⁡∫_0^t1/e^x  dx=lim(t→∞)⁡∫_0^te^(-x)  dx
=lim(t→∞)⁡〖[-e^(-x) ]_0^t 〗=lim(t→∞)⁡[-e^(-t)+1]=1  square unit

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