Compute the area between the graphs y=2x and y=x^2
The area which is shown in the fig 1.7 is:A=∫_0^2(2x-x^2 ) dx=[x^2-1/3 x^3 ]_0^2=4-8/3=4/3 square units
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The area which is shown in the fig 1.7 is:
need an explanation for this answer? contact us directly to get an explanation for this answerA=∫_0^2(2x-x^2 ) dx=[x^2-1/3 x^3 ]_0^2=4-8/3=4/3 square units