Evaluate the following integral ∫1/√(2x^2+10x+3) dx
2x^2+10x+3=2(x^2+5x)+3=2(x^2+5x+25/4-25/4)+3=2(x^2+5x+25/4)-2.25/4+3=2(x+5/2)^2-19/2I=1/√2 ∫1/(√((x+5/2)^2 )-19/4) dx=1/√2 cosh^(-1)(((2x+5))/√19)+c
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2x^2+10x+3=2(x^2+5x)+3
need an explanation for this answer? contact us directly to get an explanation for this answer=2(x^2+5x+25/4-25/4)+3
=2(x^2+5x+25/4)-2.25/4+3
=2(x+5/2)^2-19/2
I=1/√2 ∫1/(√((x+5/2)^2 )-19/4) dx=1/√2 cosh^(-1)(((2x+5))/√19)+c