Evaluate the following integral ∫1/(x^2-6x+7) dx
x^2-6x+7=x^2-6x+9-9+7=(x^2-6x+9)-9+7=(x-3)^2-2I=∫1/((x-3)^2-2) dx=(-1)/√2 tanh^(-1)(x/√2)+c
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x^2-6x+7=x^2-6x+9-9+7
need an explanation for this answer? contact us directly to get an explanation for this answer=(x^2-6x+9)-9+7
=(x-3)^2-2
I=∫1/((x-3)^2-2) dx=(-1)/√2 tanh^(-1)(x/√2)+c