Q:

Evaluate the following integral ∫1/(x^2-6x+7) dx

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Evaluate the following integral  ∫1/(x^2-6x+7) dx

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x^2-6x+7=x^2-6x+9-9+7
=(x^2-6x+9)-9+7
=(x-3)^2-2
I=∫1/((x-3)^2-2) dx=(-1)/√2  tanh^(-1)⁡(x/√2)+c

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