Evaluate the following integral I=∫x e^(x^2 ) dx

Put z =x^2 then dz=2xdxI=1/2 ∫e^z dz=e^z/2+c=e^(x^2 )/2+c

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Put z =x^2 then dz=2xdx

need an explanation for this answer? contact us directly to get an explanation for this answerI=1/2 ∫e^z dz=e^z/2+c=e^(x^2 )/2+c