Evaluate the following integral ∫_0^1x e^x dx
∫_0^1x e^x dx integrate by partsu=x dv=e^x dxdu=dx v=e^x I=├ xe^x ┤|_0^1-∫_0^1e^x dx=e-[e^x ]_0^1=e-e+1=1
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∫_0^1x e^x dx integrate by parts
need an explanation for this answer? contact us directly to get an explanation for this answeru=x dv=e^x dx
du=dx v=e^x
I=├ xe^x ┤|_0^1-∫_0^1e^x dx=e-[e^x ]_0^1=e-e+1=1