The probability that Heba passes Math 2/13 and the probability that she passes English is 4/9 . if the probability of passing both courses is 1/4 , what is the probability that Heba will pass neither Math nor English?
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A={Heba passes Math} B={Heba passes English}
need an explanation for this answer? contact us directly to get an explanation for this answerP(A)=2/3 ,P(B)=4/9 ,P(A∩B)=1/4
P(A^c∩B^c )=P〖(A∪B)〗^c=1-P(A∪B)=1-31/36=5/36