Let A= event that a family has children of both sexes, and Let B= event that a family has at most one boy. Show that A and B are independent events if a family has three children.
Let A= event that a family has children of both sexes, and Let B= event that a family has at most one boy. Show that A and B are independent events if a family has three children.
S={bbb,bbg,bgb,bgg,gbb,gbg,ggb,ggg} A={bbg,bgb,bgg,gbb,gbg,ggb} ∴P(A)=6/8=3/4 B={bgg,gbg,ggb,ggg} ∴P(B)=4/8=1/2 A∩B={bgg,gbg,ggb} P(A∩B)=3/8 Since P(A)*P(B)=3/4*1/2=3/8=P(A∩B) Then A and B are independent.
S={bbb,bbg,bgb,bgg,gbb,gbg,ggb,ggg}
need an explanation for this answer? contact us directly to get an explanation for this answerA={bbg,bgb,bgg,gbb,gbg,ggb}
∴P(A)=6/8=3/4
B={bgg,gbg,ggb,ggg}
∴P(B)=4/8=1/2
A∩B={bgg,gbg,ggb}
P(A∩B)=3/8
Since P(A)*P(B)=3/4*1/2=3/8=P(A∩B)
Then A and B are independent.