Tossing a die one time, let A be the event that an odd number occurs, B that a prime number occurs, find A∩B.
n(S)=(6)^1=6S={1,2,3,4,5,6}A={1,3,5}B={2,3,5}Then A∩B={3,5} is the event that an odd prime number occur.
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n(S)=(6)^1=6
need an explanation for this answer? contact us directly to get an explanation for this answerS={1,2,3,4,5,6}
A={1,3,5}
B={2,3,5}
Then
A∩B={3,5} is the event that an odd prime number occur.