In tossing a die one time what is the probability that the number of dots up is greater than 8?
S={1,2,3,4,5,6} ,n(s)=6^1=6C={number of dots up is greater than 8}C=∅ ,n(C)=0P(C)=(n(C))/(n(S))=P(∅)=0
total answers (1)
start bookmarking useful questions and collections and save it into your own study-lists, login now to start creating your own collections.
S={1,2,3,4,5,6} ,n(s)=6^1=6
need an explanation for this answer? contact us directly to get an explanation for this answerC={number of dots up is greater than 8}
C=∅ ,n(C)=0
P(C)=(n(C))/(n(S))=P(∅)=0