In tossing a die one time what is the probability that the number of dots up is Less than 4
S={1,2,3,4,5,6} ,n(s)=6^1=6B={number of dots up is less than 4}B={1,2,3} ,n(B)=3P(B)=(n(B))/(n(S))=3/6=0.5
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S={1,2,3,4,5,6} ,n(s)=6^1=6
need an explanation for this answer? contact us directly to get an explanation for this answerB={number of dots up is less than 4}
B={1,2,3} ,n(B)=3
P(B)=(n(B))/(n(S))=3/6=0.5