Q:

There are two circles C1 with radius r1, central coordinate (x1, y1) and C2 with radius r2 and central coordinate (x2, y2)

0

There are two circles C1 with radius r1, central coordinate (x1, y1) and C2 with radius r2 and central coordinate (x2, y2)
Write a Java program to test the followings -
"C2 is in C1" if C2 is in C1
"C1 is in C2" if C1 is in C2
"Circumference of C1 and C2 intersect" if circumference of C1 and C2 intersect, and
"C1 and C2 do not overlap" if C1 and C2 do not overlap. 

Input:

Input numbers (real numbers) are separated by a space.

Expected Output:

Input x1, y1, r1: (numbers are separated by a space)
 5 6 8 7
Input x2, y2, r2: (numbers are separated by a space)
 8 9 5 4
C1 and C2  do not overlap 

All Answers

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 import java.util.Scanner;
public class Main
{
	public static void main(String arg[])
	{
		Scanner in=new Scanner(System.in);
		    System.out.println("Input x1, y1, r1: (numbers are separated by a space)");
			double x1 = in.nextDouble(),y1=in.nextDouble(),r1=in.nextDouble();
			System.out.println("Input x2, y2, r2: (numbers are separated by a space)");
			double x2 = in.nextDouble(),y2=in.nextDouble(),r2=in.nextDouble();
			double l = Math.sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2));
			if(l>r1+r2)
				System.out.println("Circumference of C1  and C2  intersect");
			else if(r1>l+r2)
				System.out.println("C2  is in C1");
			else if(r2>l+r1)
				System.out.println("C1  is in C2");
			else
				System.out.println("C1 and C2  do not overlap");
		}
}

Sample Output:

Input x1, y1, r1: (numbers are separated by a space)
 5 6 8 7
Input x2, y2, r2: (numbers are separated by a space)
 8 9 5 4
C1 and C2  do not overlap

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