Simplify the following Boolean function F(x,y,z) = x’y’z’ + x’y + xyz’ +xz to a minimum number of literals using algebraic manipulation and implement
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= x’y’z’ + x’y + xyz’ +xz
= x’ (y’z’ + y) + x (yz’ + z)
= x’ [(y + y’) (y + z’)] + x [(y + z) (z + z’)]
= x’ [(1) (y + z’)] + x [(y + z) (1)]
= x’ (y + z’) + x (y + z)
= x’y + x’z’ + xy +xz
= x’y + xy + x’z’ + xz
= y (x’+x) + x’z’ + xz
= y (1) + x’z’ +xz
=y + x’z’ + xz
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