Use DeMorgan’s Theorems to simplify the following expressions:
F = (B’D) (A’ + C’D) + (BC’+D’A)
F = [(B’D) (A’ + C’D) + (BC’+D’A)]’
F = (B’D)’ + (A’+C’D)’ (BC’+D’A)’
F = (B+D’) + A(C+D’) (B’+C)(D+A’)
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F = (B’D) (A’ + C’D) + (BC’+D’A)
F = [(B’D) (A’ + C’D) + (BC’+D’A)]’
F = (B’D)’ + (A’+C’D)’ (BC’+D’A)’
F = (B+D’) + A(C+D’) (B’+C)(D+A’)
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