Use algebraic manipulation to simplify the following expression
a. F(A,B,C) = A’ + ABC + A(B⊕C) + AB’C’
F = A’ + ABC + A(B⊕C) + AB’C’
= A’ + ABC + AB’C + ABC’ + AB’C’
= A’ + AB(C+C’) + AB’(C+C’)
= A’ + AB + AB’
= A’ + A (B+B’)
= A’ + A
= 1
total answers (1)
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F = A’ + ABC + A(B⊕C) + AB’C’
= A’ + ABC + AB’C + ABC’ + AB’C’
= A’ + AB(C+C’) + AB’(C+C’)
= A’ + AB + AB’
= A’ + A (B+B’)
= A’ + A
= 1
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