Q:

The following ABG results were obtained on a 54-year-old female patient that is breathing room air:

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The following ABG results were obtained on a 54-year-old female patient that is breathing room air:

patient that is breathing room air:

pH 7.30

PaCO2 57 torr

PaO2 61 torr

HCO3- 24 mEq/L

Which of the following best describes the given results?


  1. Normal blood gas with mild hypoxemia
  2. Fully compensated metabolic acidosis with mild hypoxemia
  3. Acute respiratory alkalosis with mild hypoxemia
  4. Acute uncompensated respiratory acidosis with mild hypoxemia

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This is just a classic ABG interpretation question. You likely won’t see many of these on the TMC Exam because at this point, the NBRC will assume that you already know how to interpret ABGs. Otherwise, you wouldn’t have made it this far.

With that said, you still absolutely MUST know how to interpret them because you will be required to do so for SEVERAL questions on the exam.

So now let’s interpret this one.

The pH decreased which means acidosis. The PaCO2 is increased and the Bicarb is in the normal range. This tells us that there respiratory acidosis with no compensation because the Bicarb is normal. The PaO2 is decreased as well, which tells us that there is hypoxemia. So we know that the correct answer is D.

The correct answer is: D. Acute uncompensated respiratory acidosis with mild hypoxemia

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