Write a C Program to Count Lines,Blank Lines,Comments in File

Below is the source code for C Program to Count Lines, Blank Lines, Comments in File which is successfully compiled and run on Windows System to produce desired output as shown below. Here, file4.txt contains the code of this program in notepad.

SOURCE CODE : :

/*  C Program to Count Lines, Blank Lines, Comments in File  */

#include <stdio.h>

int main()
{
    int line_count = 0, n_o_c_l = 0, n_o_n_b_l = 0, n_o_b_l = 0, n_e_c = 0;
    FILE *fp1;
    char ch;
    char * arrr = "C:\\Users\\acer\\Documents\\file4.txt";
    fp1 = fopen(arrr, "r");

    while ((ch = fgetc(fp1))!= EOF)
    {
        if (ch  ==  '\n')
        {
            line_count++;
        }
        if (ch  ==  '\n')
        {
            if ((ch = fgetc(fp1))  ==  '\n')
            {
                fseek(fp1, -1, 1);
                n_o_b_l++;
            }
        }
        if (ch  ==  ';')
        {
            if ((ch = fgetc(fp1))  ==  '\n')
            {
                fseek(fp1, -1, 1);
                n_e_c++;
            }
        }
    }
    fseek(fp1, 0, 0);
    while ((ch = fgetc(fp1))!= EOF)
    {
        if (ch  ==  '/')
        {
            if ((ch = fgetc(fp1))  ==  '/')
            {
                n_o_c_l++;
            }
        }
    }
    printf("Total no of lines: %d\n", line_count);
    printf("Total no of comment line: %d\n", n_o_c_l);
    printf("Total no of blank lines: %d\n", n_o_b_l);
    printf("Total no of non blank lines: %d\n", line_count-n_o_b_l);
    printf("Total no of lines end with semicolon: %d\n", n_e_c);

    return 0;
}

OUTPUT : :

Total no of lines: 54
Total no of comment line: 0
Total no of blank lines: 4
Total no of non blank lines: 50
Total no of lines end with semicolon: 18

Above is the source code for C Program to Count Lines, Blank Lines, Comments in File which is successfully compiled and run on Windows System.The Output of the program is shown above .