Calculate the half-life time of a radioactive isotope given that the initial count rate was 890 Bq & after 180 min. the count rate was found to be 750 Bq
t ½ = 0.693 × t ÷ ln A0/A
t1/2 = 0.693 × 180 ÷ ln (890 / 750)
t1/2 = 728.84 min
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t ½ = 0.693 × t ÷ ln A0/A
t1/2 = 0.693 × 180 ÷ ln (890 / 750)
t1/2 = 728.84 min
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