Find the output of Java programs | if else | Set 1: Enhance the knowledge of Java if else concepts by solving and finding the output of some Java programs.
Question 1:
public class Main {
public static void main(String[] args) {
int num = 101;
if (num = 101) {
System.out.println("Hello");
}
else {
System.out.println("Hiiii");
}
}
}
Question 2:
public class Main {
public static void main(String[] args) {
int A = 10;
int B = 20;
int C = 30;
C = ++A * --B + C;
if (A == (++B * 2)) {
System.out.println("Hello: " + C);
}
else {
System.out.println("Hiii: " + C);
}
}
}
Question 3:
public class Main {
public static void main(String[] args) {
float A = 2.34F;
double B = 2.34;
if (A == B) {
System.out.println("www.includehelp.com");
}
else {
System.out.println("www.google.com");
}
}
}
Question 4:
public class Main {
public static void main(String[] args) {
int A = -2;
if (A > null) {
System.out.println("www.includehelp.com");
}
else {
System.out.println("www.google.com");
}
}
}
Question 5:
public class Main {
public static void main(String[] args) {
int NUM = 0;
String STR = "Hello World";
NUM = STR.length();
if (NUM % 2 == 0) {
System.out.println("NUM is EVEN number");
}
else {
System.out.println("NUM is ODD number");
}
}
}
Java programming
Answer Question 1:
Output:
Main.java:5: error: incompatible types: int cannot be converted to boolean if (num = 101) { ^ 1 errorExplanation:
The above program will generate a syntax error because the if condition in Java required boolean value. In the if condition, we assign variable num with 101. The condition will be:
if(101)We cannot use integer value for conditions in Java.
Answer Question 2:
Output:
Explanation:
In the above program, we created a class Main that contains a main() method, the main() method is the entry point of the program, here we declared three integer variables A, B, and C initialized with 10, 20, 30.
Now evaluate the expression:
C = ++A * --B + C;First, evaluate ++A, then A becomes 11, and then evaluate --B, then B becomes 19.
C = A *B + C; C = 11*19+30; C = 209+30 C = 239Let's check the condition given below,
if (A==(++B*2)) if (A==(20*2)) if (A==400)A contains 11 then the if condition will false that's why "Hiii: 239" will be printed on the console screen.
Answer Question 3:
Output:
Explanation:
In the above program, we created a class Main that contains a main() method, the main() method is the entry point of the program, here we declared two variables A and B that are initialized with "2.34F" and "2.34" respectively.
Here, A is float type, and B is double type then both numbers will not equal then condition get false and www.google.com will print on the console screen.
Answer Question 4:
Output:
Main.java:5: error: bad operand types for binary operator '>' if (A > null) { ^ first type: int second type: <null> 1 errorExplanation:
The above program will generate a syntax error because we cannot compare the integer variable with null.
Answer Question 5:
Output:
Explanation:
In the above program, we created a class Main that contains a main() method, the main() method is the entry point of the program, here we declared two variables NUM and STR that are initialized with 0 and "Hello World" respectively.
NUM = STR.length();Here, STR.Length() method will return 11 and assigned to the variable NUM.
if (NUM%2==0) if (11%2==0)In the above condition, we will get remainder 1, and then the condition gets false and print "NUM is ODD number" on the console screen.
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