Q:

Java program to print the following pattern

robaa
Save to bookmark
|
2022-11-13
|
  231 
0

Algorithm:

  • STEP 1: START
  • STEP 2: SET i=1,j=1,k=1,l=1,direction=1
  • STEP 3: SET matrix[5][5]
  • STEP 4: REPEAT STEP 5 to 9 UNTIL i is less than 5
  • STEP 5: SET j=0
  • STEP 6: REPEAT STEP 7 and 8 UNTIL j is less than 5
  • STEP 7: SET matrix[i][j]=0
  • STEP 8: SET j=j+1
  • STEP 9: SET i=i+1
    // steps for printing the matrix
  • STEP 10: SET i=0
  • STEP 11: REPEAT STEP 12 to 16 UNTIL i is less than 5
  • STEP 12: SET j=0
  • STEP 13: REPEAT STEP 14 and 15 UNTIL j is less than 5
  • STEP 14: PRINT matrix[i][j]
  • STEP 15: SET j=j+1
  • STEP 16: SET i=i+1
                  //steps for snake
  • STEP 17: SET i=1
  • STEP 18: SET j=0
  • STEP 19: SET k=0
  • STEP 20: REPEAT STEP 21 to 26 UNTIL i is less than 16
  • STEP 21: SET matrix[j][k]=i
  • STEP 22: IF direction=1
                  IF k+1<5
                  IF matrix[j][k+1]==0
                  SET k=k+1
                  ELSE SET j=j+1 and SET direction =2
                  ELSE SET j= j+1 and SET direction =2
  • STEP 23: IF direction=2
                  IF j+1<5
                  IF matrix[j+1][k]==0
                  SET j=j+1
                  ELSE SET k=k-1 and SET direction =3
                  ELSE SET k= -1 and SET direction =3
  • STEP 24: IF direction=3
                  IF k-1>=0
                  IF matrix[j][k-1]==0
                  SET k=k-1
                  ELSE SET j=j-1 and SET direction =4
                  ELSE SET j= j-1 and SET direction =4
  • STEP 25: IF direction=4               IF j-1>=0
                  IF matrix[j-1][k]==0
                  SET j=j-1
                  ELSE SET k=k+1 and SET direction =1
                  ELSE SET k= k+1 and SET direction =1
  • STEP 26: SET i=i+1
                  // Steps for printing the matrix
  • STEP 27: SET i=0
  • STEP 28: REPEAT STEP 29 to 33 UNTIL i is less than 5
  • STEP 29: SET j=0
  • STEP 30: REPEAT STEP 31 and 32 UNTIL j is less than 5
  • STEP 31: PRINT matrix[i][j]
  • STEP 32: SET j=j+1
  • STEP 33: SET i=i+1
  • STEP 34: END
Java programming, examples, Java programming examples,
login and add your own answer to this question

All Answers

robaa
2022-11-13
need an explanation for this answer? contact us directly to get an explanation for this answer

Program:

public class pattern{    
    public static void main(String []args){    
   int matrix[][]=new int[5][5];    
   int i,j,k,l;    
   int direction=1;    
   for(i=0;i<5;i++){    
       for(j=0;j<5;j++){    
          matrix[i][j]=0;     
       }    
   }    
          
   for(i=1,j=0,k=0;i<=16;i++){    
       matrix[j][k]=i;    
           
       switch(direction){    
           case 1:if(k+1<5){    
                       if(matrix[j][k+1]==0){    
                           k++;    
                           continue;    
                       }    
                       else{    
                               
                           j++;    
                           direction=2;    
                           continue;    
                       }    
                   }    
                      
                  else{    
                       j++;    
                       direction=2;    
                       continue;    
                   }    
               
               
               
               
           case 2:if(j+1<5){    
                           
                       if(matrix[j+1][k]==0){    
                           j++;    
                           continue;    
                       }    
                       else{    
                           direction=3;    
                           k--;    
                           continue;    
                       }    
                   }    
                   else{    
                           direction=3;    
                           k--;    
                           continue;    
                       }    
                      
               
               
               
           case 3:if(k-1>=0){    
                       if(matrix[j][k-1]==0){    
                               
                           k--;    
                           continue;    
                       }    
                       else{    
                           direction=4;    
                           j--;    
                           continue;    
                       }    
                   }    
                   else{    
                           direction=4;    
                           j--;    
                           continue;    
                       }    
                       
                                     
           case 4:if(j-1>=0){    
                       if(matrix[j-1][k]==0){    
                               
                           j--;    
                           continue;    
                       }    
                       else{    
                           k++;    
                           direction=1;    
                           continue;    
                       }    
                   }    
                   else{    
                           k++;    
                           direction=1;    
                           continue;    
                       }             
       }    
   }    
 for(i=0;i<5;i++){    
       for(j=0;j<5;j++){    
           if(matrix[i][j]==0){    
               System.out.print("\t");    
           }    
           else{    
               System.out.print(matrix[i][j]+"\t");     
           }            
       }    
       System.out.println("");    
   }    
    }

Output:

need an explanation for this answer? contact us directly to get an explanation for this answer

total answers (1)

This question belongs to these collections

Similar questions

need a help?

find thousands of online teachers now