Q:

A household light globe with a power rating of 60 W operates at a potential difference of 240 V and has a resistance of 960 . Using this information and Ohm’s law, the current (I) may be calculated to be

waelhammad
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2022-10-21
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A household light globe with a power rating of 60 W operates at a potential difference of 240 V and has a resistance of 960 . Using this information and Ohm’s law, the current (I) may be calculated to be

  1. I = V ÷ R = 240 ÷ 960 = 0.25 A
  2. I = R ÷ V = 960 ÷ 240 = 4 A
  3. I = P ÷ V = 60 ÷ 240 = 0.25 A
  4. I = V ÷ P = 240 ÷ 60 = 4 A
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waelhammad
2022-10-21
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A: Ohm’s law: V = I × R, so I = V ÷ R. Choice C also produces the correct answer for current, but does not use Ohm’s law.

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