In the following nuclear reaction, 92 238 2 4 U H → + X e , one of the products (2 4 He) is an alpha particle. What is the other product (X)?
belongs to book: Examination Questions and Answers in Basic Anatomy and Physiology|Martin Caon|| Chapter number:17.2| Question number:25
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Medicine
A: Consider the mass numbers: 238 − 4 = 234. Then the atomic numbers: 92 − 2 = 90. Hence the nuclide X must be Thorium 234.
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