Write a Java method to find number is even number or not
In this demo I have used NetBeans IDE 8.2 for debugging purpose. But you can use any java programming language compiler as per your availability..
import java.util.Scanner; public class Javaexcercise { public static void main(String[] args) { Scanner console = new Scanner(System.in); int num; System.out.print("Enter an integer: "); num = console.nextInt(); if(isEven(num)) { System.out.println("Number is even"); } else { System.out.println("Number is odd"); } } public static boolean isEven(int number) { if(number % 2 == 0) { return true; } else { return false; } } }
Result:
Enter an integer: 222
Number is even
total answers (1)
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In this demo I have used NetBeans IDE 8.2 for debugging purpose. But you can use any java programming language compiler as per your availability..
Result:
Enter an integer: 222
Number is even
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