Rust program to pass a channel to the function

Program/Source Code:

The source code to pass a channel to the function is given below. The given program is compiled and executed on UBUNTU 18.04 successfully.

// Rust program to pass a channel 
// to the function

use std::thread;
use std::sync::mpsc;

fn fun(chnl: mpsc::Sender<i32>) {
    // Send a integer value
    chnl.send(786).unwrap();
}

fn main() {
    let (tx, rx) = mpsc::channel();
    
    thread::spawn(move || {
        // Pass channel as a parameter.
        fun(tx);
    });
    
    // Receive message from thread.
    let val = rx.recv().unwrap();
    println!("Message received: {}", val);
}

Output:

$ rustc main.rs

$ ./main
Message received: 786

Explanation:

Here, we created two functions fun() and main(). The fun() function accepts the channel as a parameter and sends the message to the main thread. And, we created a thread and called the fun() function to send a message. Then we received the message using the recv() function and printed the received message.