The source code to find the remainder without using the modulus (%) operator is given below. The given program is compiled and executed successfully.
// Rust program to find the remainder
// without using '%' operator
use std::io;
fn main() {
let mut n1:i32 = 0;
let mut n2:i32 = 0;
let mut rem:i32 = 0;
let mut input1 = String::new();
let mut input2 = String::new();
println!("Enter number1: ");
io::stdin().read_line(&mut input1).expect("Not a valid string");
n1 = input1.trim().parse().expect("Not a valid number");
println!("Enter number2: ");
io::stdin().read_line(&mut input2).expect("Not a valid string");
n2 = input2.trim().parse().expect("Not a valid number");
rem=n1-(n1/n2)*n2;
println!("Remainder is: {}",rem);
}
Output:
RUN 1:
Enter number1:
66
Enter number2:
3
Remainder is: 0
RUN 2:
Enter number1:
9
Enter number2:
5
Remainder is: 4
Explanation:
Here, we read the value of n1, n2 from the user. Then we found the remainder without using the modulus '%' operator. After that, we printed the result.
Program/Source Code:
The source code to find the remainder without using the modulus (%) operator is given below. The given program is compiled and executed successfully.
Output:
Explanation:
Here, we read the value of n1, n2 from the user. Then we found the remainder without using the modulus '%' operator. After that, we printed the result.
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