Finding the Square Root of the Complex Number in Golang

Consider the below examples explaining – how to find the square root of the complex numbers in Golang?

Example 1:

// Golang program to demonstrate how to find
// the square root of the given complex number

package main

import (
	"fmt"
	"math/cmplx"
)

// Main function
func main() {
	fmt.Printf("cmplx.Sqrt(10 - 15i): %.2f\n", cmplx.Sqrt(10-15i))
	fmt.Printf("cmplx.Sqrt(-3 - 9i) : %.2f\n", cmplx.Sqrt(-3-9i))
	fmt.Printf("cmplx.Sqrt(9 - 16i) : %.2f\n", cmplx.Sqrt(9-16i))
}

Output:

cmplx.Sqrt(10 - 15i): (3.74-2.00i)
cmplx.Sqrt(-3 - 9i) : (1.80-2.50i)
cmplx.Sqrt(9 - 16i) : (3.70-2.16i)

Example 2:

// Golang program to demonstrate how to find
// the square root of the given complex number

package main

import (
	"fmt"
	"math/cmplx"
)

// Main function
func main() {
	// Creating complex numbers
	x := complex(0, 2)
	y := complex(4, 6)

	// Finding the square roots
	sqrt_x := cmplx.Sqrt(x)
	sqrt_y := cmplx.Sqrt(y)

	// Displaying complex numbers and square roots
	fmt.Println("x: ", x)
	fmt.Println("y: ", y)
	
	fmt.Println("Square root of", x, "is", sqrt_x)
	fmt.Println("Square root of", y, "is", sqrt_y)
}

Output:

x:  (0+2i)
y:  (4+6i)
Square root of (0+2i) is (1+1i)
Square root of (4+6i) is (2.3676045437243083+1.2671034983236331i)