1D array using the dynamic memory allocation in C

#include <stdio.h>
#include <stdlib.h>
#define FAIL 1
#define TRUE 0
int main(int argc, char *argv[])
{
    int *piBuffer = NULL; //pointer to integer
    int nBlock = 0; //Variable store number of block
    int iLoop = 0; //Variable for looping
    printf("\nEnter the number of block = ");
    scanf("%d",&nBlock); //Get input for number of block
    piBuffer = (int *)malloc(nBlock * sizeof(int));
    //Check memory validity
    if(piBuffer == NULL)
    {
        return FAIL;
    }
    //copy iLoop to each block of 1D Array
    for (iLoop =0; iLoop < nBlock; iLoop++)
    {
        piBuffer[iLoop] = iLoop;
    }
    //Print the copy data
    for (iLoop =0; iLoop < nBlock; iLoop++)
    {
        printf("\npcBuffer[%d] = %d\n", iLoop,piBuffer[iLoop]);
    }
    // free allocated memory
    free(piBuffer);
    return TRUE;
}

Output:

Enter the number of block = 7

pcBuffer[0] = 0

pcBuffer[1] = 1

pcBuffer[2] = 2

pcBuffer[3] = 3

pcBuffer[4] = 4

pcBuffer[5] = 5

pcBuffer[6] = 6