C program to find the generic root of a number

The below program ask the user to enter the value. After getting the value from the user it will find the generic root of a number.

#include <stdio.h>
int main()
{
    int num, sum, rem;
    printf("Please Enter any number = ");
    scanf("%d", &num);
    while(num >= 10)
    {
        for (sum=0; num > 0; num= num/10)
        {
            rem = num % 10;
            sum=sum + rem;
        }
        if(sum >= 10)
        {
            num = sum;
        }
        else
        {
            printf("Generic Root of Given num = %d", sum);
            break;
        }
    }
    return 0;
}

Output:

Please Enter any number = 123
Generic Root of Given num = 6

You can also calculate the genric root of a number by modulo division 9. There are two conditions, calculate num % 9 to get the root if the result is 0, then the root is 9.

#include <stdio.h>
int main()
{
    int num, genericRoot;
    printf("Please Enter any number = ");
    scanf("%d", &num);
    genericRoot = (1+((num-1)%9));
    printf("Generic Root of a given Number = %d", genericRoot);
    return 0;
}

Output:

Please Enter any number = 123
Generic Root of Given num = 6