C Program to Find the Roots of a Quadratic Equation using if-else

The below program ask the user to enter the value of a,b and c. After getting the value from the user it will calculate on the basis of ‘Discriminant’ value.

#include <stdio.h>
#include <math.h>
int main()
{
    float a, b, c;
    float root1, root2, imaginary;
    float discriminant;
    printf("Enter value of a of quadratic equation (aX^2 + bX + c): ");
    scanf("%f", &a);
    printf("Enter value of b of quadratic equation (aX^2 + bX + c): ");
    scanf("%f",&b);
    printf("Enter values of c of quadratic equation (aX^2 + bX + c): ");
    scanf("%f",&c);
    // Find discriminant of the equation
    discriminant = (b * b) - (4 * a * c);
    //Check different cases for the discriminant
    if(discriminant > 0)
    {
        root1 = (-b + sqrt(discriminant)) / (2*a);
        root2 = (-b - sqrt(discriminant)) / (2*a);
        printf("Two distinct and real roots exists: %.2f and %.2f", root1, root2);
    }
    else if(discriminant == 0)
    {
        root1 = root2 = -b / (2 * a);
        printf("Two equal and real roots exists: %.2f and %.2f", root1, root2);
    }
    else if(discriminant < 0)
    {
        root1 = root2 = -b / (2 * a);
        imaginary = sqrt(-discriminant) / (2 * a);
        printf("Two distinct complex roots exists: %.2f + i%.2f and %.2f - i%.2f",
               root1, imaginary, root2, imaginary);
    }
    return 0;
}

Output:

Enter value of a of quadratic equation (aX^2 + bX + c): 2
Enter value of b of quadratic equation (aX^2 + bX + c): 7
Enter values of c of quadratic equation (aX^2 + bX + c): 2
Two distinct and real roots exist: -0.31 and -3.19