(Revise selection sort) In Section 7.11, you used selection sort to sort an array. The selection-sort method repeatedly finds the smallest number in the current array and swaps it with the first

/*********************************************************************************
* (Revise selection sort) In Section 7.11, you used selection sort to sort an    *
* array. The selection-sort method repeatedly finds the smallest number in the   *
* current array and swaps it with the first. Rewrite this program by finding the *
* largest number and swapping it with the last. Write a test program that reads  *
* in ten double numbers, invokes the method, and displays the sorted numbers.    *
*********************************************************************************/
import java.util.Scanner;

public class Exercise_07_20 {
	/** Main method */
	public static void main(String[] args) {
		Scanner input = new Scanner(System.in);
		double[] numbers = new double[10]; // Create an array of length 10

		// Prompt the user to enter ten numbers
		System.out.print("Enter ten numbers: ");
		for (int i = 0; i < numbers.length ; i++)
			numbers[i] = input.nextDouble();

		// Invoke selectionSort
		selectionSort(numbers);

		// Display the sorted numbers
		for (double e: numbers) 
			System.out.print(e + " ");
		System.out.println();
	}

	/** selsctionSort sorts array in accending order */
	public static void selectionSort(double[] list) {
		for (int i = list.length - 1; i >= 0; i--) {
			// Find the maximum in the list[i+1...list.length]
			double currentMax = list[i];
			int currentMaxIndex = i;

			for (int j = i - 1; j >= 0; j--) {
				if (currentMax < list[j]) {
					currentMax = list[j];
					currentMaxIndex = j;
				}
			}

			// Swap list[i] with list[currentMax] if necessary
			if (currentMaxIndex != i) {
				list[currentMaxIndex] = list[i];
				list[i] = currentMax;
			}
		}
	}
}