Q:

The inverse s-box permutation follows

mhmadesk
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2022-06-01
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The inverse s-box permutation follows

-  b’i = b(i+2) XOR b(i+5) XOR b(i+7) XOR di Here di is –

  1. di is the ith bit of a byte ‘d’ whose hex value is 0x15
  2. di is the ith bit of a byte ‘d’ whose hex value is 0x05
  3. di is the ith bit of a byte ‘d’ whose hex value is 0x25
  4. di is the ith bit of a byte ‘d’ whose hex value is 0x51
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mhmadesk
2022-06-01
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 (b).di is the ith bit of a byte ‘d’ whose hex value is 0x05

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