Q:

In AES, to make the s-box, we apply the transformation

0

In AES, to make the s-box, we apply the transformation 

b’i = bi XOR b(i+4) XOR b(i+5) XOR b(i+6) XOR b(i+7) XOR ci What is ci in this transformation?


  1. ci is the ith bit of byte c with value 0x63
  2. ci is the ith bit of byte c with value 0x25
  3. ci is the ith bit of byte c with value 0x8F
  4. ci is the ith bit of byte c with value 0x8A

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 (a).ci is the ith bit of byte c with value 0x63

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