In AES, to make the s-box, we apply the transformation
b’i = bi XOR b(i+4) XOR b(i+5) XOR b(i+6) XOR b(i+7) XOR ci What is ci in this transformation?
- ci is the ith bit of byte c with value 0x63
- ci is the ith bit of byte c with value 0x25
- ci is the ith bit of byte c with value 0x8F
- ci is the ith bit of byte c with value 0x8A
(a).ci is the ith bit of byte c with value 0x63
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