Q:

Repeat Example CAEHW by choosing x =

0

Repeat Example CAEHW by choosing 

and then arrive at an eigenvalue   and eigenvector of the matrix A. The hard way.

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Form the matrix C whose columns are x, Ax, A2x, A3x, A4x, A5x and row- reduce the matrix,

The simplest possible relation of linear dependence on the columns of C comes from using 

scalars α4  1 and α5 = α6 = 0 for the free variables in a solution to LS(C, 0). 

The remainder of this solution is α1 = 3, α2 = 1, α3 = 3. 

This solution gives rise to the polynomial

p(x) = 3  x  3x2 + x3 = (x  3)(x  1)(x + 1)

which then has the property that p(A)x = 0.

No matter how you choose to order the factors of p(x), the value of k (in the language of

 Theorem EMHE and Example CAEHW) is k = 2. 

For each of the three possibilities, we list the resulting eigenvector and the associated eigenvalue:

Note that each of these eigenvectors can be simplified by an appropriate scalar multiple,

but we have shown here the actual vector obtained by the product specified in the theorem.

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