Find the eigenvalues, eigenspaces, algebraic and geometric multiplicities for the 3 × 3 identity matrix I3. Do your results make sense?
belongs to book: A First Course in Linear Algebra|Robert A. Beezer|| Chapter number:6| Question number:C25
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The characteristic polynomial for A = I3
is pI3 (x) = (1- x)3
which has eigenvalue λ = 1 with algebraic multiplicity αA (1) = 3. Looking for eigenvectors, we find that A − λI =
The nullspace of this matrix is all of C3, so that the eigenspace is
and the geometric multiplicity is γA(1) = 3.
Does this make sense? Yes! Every vector x is a solution to I3x = 1x, so every nonzero vector is an eigenvector with eigenvalue 1. Since every vector is unchanged when multiplied by I3, it makes sense that λ = 1 is the only eigenvalue.
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