Solve the given matrix equation for α, or explain why no solution exists:
belongs to book: A First Course in Linear Algebra|Robert A. Beezer|| Chapter number:3| Question number:C13
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total answers (1)
belongs to book: A First Course in Linear Algebra|Robert A. Beezer|| Chapter number:3| Question number:C13
total answers (1)
The given equation
gives a system of six equations in α:
3α − 4 = 2
α − 1 = 1
2α − 3 = 1
−2 = −2
α = 2
4α − 1 = 6.
Solving each of these equations, we see that the first three and the fifth all lead to the solution α = 2, the fourth equation is true no matter what the value of α, but the last equation is only solved by α = 7/4. Thus, the system has no solution, and the original matrix equation also has no solution.
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