Java Program to check Armstrong number

import java.util.Scanner;
 
class demo1
{
   public static void main(String args[])
   {
      int n, sum = 0, temp, remainder, digits = 0;
 
      Scanner in = new Scanner(System.in);
      System.out.println("Input a number");      
      n = in.nextInt();
      temp = n;
      while (temp != 0) {
         digits++;
         temp = temp/10;
      }
      temp = n;
      while (temp != 0) {
         remainder = temp%10;
         sum = sum + power(remainder, digits);
         temp = temp/10;
      }
      if (n == sum)
         System.out.println(n + " is an Armstrong number.");
      else
         System.out.println(n + " isn't an Armstrong number.");         
   }
   static int power(int n, int r) {
      int c, p = 1;
 
      for (c = 1; c <= r; c++) 
         p = p*n;
 
      return p;   
   }
}