Slice list into 3 equal chunks and reverse each chunk using python programming

Hint:

• Divide the length of a list by 3 to get the each chunk size
• Run loop three times and use the slice() function to get the chunk and reverse it

Solution:

• Get the length of a list using a len() function
• Divide the length by 3 to get the chunk size
• Run loop three times
• In each iteration, get a chunk using a slice(start, end, step) function and reverse it using the reversed() function
• In each iteration, start and end value will change

sample_list = [11, 45, 8, 23, 14, 12, 78, 45, 89]
print("Original list ", sample_list)

length = len(sample_list)
chunk_size = int(length / 3)
start = 0
end = chunk_size

# run loop 3 times
for i in range(3):
    # get indexes
    indexes = slice(start, end)
    
    # get chunk
    list_chunk = sample_list[indexes]
    print("Chunk ", i, list_chunk)
    
    # reverse chunk
    print("After reversing it ", list(reversed(list_chunk)))

    start = end
    end += chunk_size