Perform the indicated function evaluations for f(x)=3−5x−2x2
??=f (6−t)
f(6−t) = 3−5(6−t)−2(6−t)2
3−5(6−t)−2(36−12t+t2)=
3−30+5t−72+24t−2t2=
99+29t−2t2 - =
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f(6−t) = 3−5(6−t)−2(6−t)2
3−5(6−t)−2(36−12t+t2)=
3−30+5t−72+24t−2t2=
99+29t−2t2 - =
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